Dashboard Deep Learning Power Systems Analysis Per-unit & symmetrical components Symmetrical components — Fortescue decomposition

Symmetrical components — Fortescue decomposition

Any three unbalanced phasors split uniquely into a balanced positive-sequence + a balanced negative-sequence + a zero-sequence set. The algebra behind all unbalanced fault analysis.

Sophomore ~11 min

Step 1 — Unbalanced 3-phase set: per-phase analysis breaks down

0.55×
active unbalanced V₀ V₊

Reference notes

Use Next → on the narrator above to step through Fortescue's decomposition: the unbalanced raw set, the three balanced sequence sets (positive, negative, zero), the decomposition formulae, and where the technique shows up in real power-system analysis.

Why we need this

Per-phase analysis assumes balanced three-phase: three equal magnitudes, exactly 120° apart. Most steady-state load-flow studies fit that assumption. But unbalanced conditions — single line-to-ground faults, open conductors, unbalanced loads, non-linear-load harmonics — destroy the symmetry, and a per-phase model can no longer give the right answer. Symmetrical components rescue us: any three phasors can be uniquely decomposed into three balanced sets that can be analyzed per-phase, then re-superposed.

The three sequence sets

Positive sequence (+)

Three equal-magnitude phasors, 120° apart, rotating in the same sense as the original system (A → B → C). With a = 1∠120° as the rotation operator:

V+a = reference · V+b = a²·V+a · V+c = a·V+a

This is the "normal" component — it carries real power, produces torque in motors, and is what you'd see in a perfectly balanced system.

Negative sequence (−)

Three equal-magnitude phasors, 120° apart, but rotating in the opposite sense (A → C → B). The a and a² roles swap relative to positive sequence:

V-a = reference · V-b = a·V-a · V-c = a²·V-a

Negative sequence shows up only under unbalance. In a motor it produces a braking torque, induces rotor losses, and is what relay 46 (negative-sequence overcurrent) trips on.

Zero sequence (0)

Three equal-magnitude phasors, all in phase — no rotation at all:

V0a = V0b = V0c

Their sum is 3 V₀, not zero. That means zero-sequence currents need a return path (neutral wire or earth) to flow. With no neutral, zero-sequence current is forced to zero by KCL. Triplen harmonics (3rd, 9th, 15th, …) are zero-sequence — they're in phase across all three phases, so a delta winding captures them as circulating currents and a tertiary delta protects the rest of the system from harmonic distortion.

The Fortescue decomposition formulae

Given any three phase phasors Va, Vb, Vc:

V0 = ⅓ (Va + Vb + Vc)
V+ = ⅓ (Va + a·Vb + a²·Vc)
V = ⅓ (Va + a²·Vb + a·Vc)

Notice the elegant symmetry: in V₊ we multiply V_b by a and V_c by ; in V₋ we swap them. And reconstruction is just addition:

Va = V0 + V+ + V · Vb = V0 + a²·V+ + a·V · Vc = V0 + a·V+ + a²·V

Where this matters in practice

Single line-to-ground fault

SLG faults are the most common power-system fault (about 70–80% of all faults). For a fault on phase a with the others healthy, the boundary conditions are Ib = Ic = 0 and Va = Zf · Ia. Substituting into the Fortescue matrix yields:

I+ = I = I0 = Ia / 3

So in the sequence-network model, the three networks (Z₊, Z₋, Z₀) are connected in series. The fault current is:

I+ = V+,pre-fault / (Z+ + Z + Z0 + 3Zf)

where Zf is the fault impedance (often taken as zero for bolted faults). Other fault types reduce to other interconnections of the same three sequence networks.

Transformer zero-sequence behaviour

The structural rule: a delta winding always blocks zero-sequence from crossing it; a grounded wye provides a path.

Motor protection

Continuously running an induction motor on unbalanced supply produces both negative-sequence current (which heats the rotor disproportionately) and a torque component opposing rotation. The standard rule of thumb is that a 5% voltage unbalance causes ~30% increase in motor losses — which is why ANSI relay 46 (negative-sequence overcurrent) is a core induction-motor protection element.

Take-away. Any three-phasor set decomposes into a positive-sequence set, a negative-sequence set, and a zero-sequence set. Pull them apart with the ⅓-prefactor Fortescue formulae; analyze each independently using ordinary per-phase methods on the sequence network; then superpose. SLG fault → series; LL fault → parallel + −; LLG fault → all three in a specific interconnect; balanced 3-phase fault → only positive. Symmetrical components are the algebra that makes every unbalanced-fault calculator and every protection setting study tractable.

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